WebQuestion: ion for the circle with the following properties. Center (-6,(-7)/(6)) and tangent to the x-axis. ion for the circle with the following properties. Center (-6,(-7)/(6)) and tangent to the x-axis. Expert Answer. Who are the experts? Experts are tested by Chegg as specialists in their subject area. We reviewed their content and use your ... WebOct 5, 2024 · (x-h) 2 +(y-k) 2 =4 2. Since it is tangent to the x-axis, y=0 at that point. Also, since it has the point (-5,8) on its perimeter, the circle is above the x-axis (if it goes as high as y=8 and it's radius is only 4, then the circle must be above the x-axis). But if it is tangent to the x-axis, AND its diameter is 8, then (-5,8) MUST be at the ...
Tangent Circle Formula With Solved Example - BYJU
WebQuestion: ion for the circle with the following properties. Center (-6,(-7)/(6)) and tangent to the x-axis. ion for the circle with the following properties. Center (-6,(-7)/(6)) and … WebJan 26, 2016 · The general form of a circle is (y −k)2 +(x −h)2 = r2 where (h,k) is the centre of the circle and r is the radius. Because the circle is tangent to the x axis and the y coordinate of the centre is 7, the radius r = 7 - see sketch. So the equation becomes (y −7)2 + (x −5)2 = 72 (y −7)2 + (x −5)2 = 49 Answer link imax enhanced projector
The equation of the tangent to a circle - Equations of …
WebApr 1, 2010 · What are the tangent equations to the circle x2 plus y2 -6x plus 4y plus 5 equals 0 at the points where they meet the x axis? Equation of circle: x^2 +y^2 -6x +4y +5 = 0 Completing the squares (x -3)^2 +(y +2)^2 = 8 Centre of circle: (3, -2) Radius of circle: square root of 8 Points of contact are at: (1, 0) and (5, 0) where the radii touches the x … WebJun 18, 2024 · From equation (2), the slope of the tangent at this point is $2$, so an equation of the perpendicular to this tangent is $${y-2\over x-2}=-\frac12.\tag4$$ Additionally, given two tangents to a circle, the circle’s center lies on one of the angle bisectors of those tangents. WebMay 11, 2016 · How do you write an equation for a circle with center (3,5) tangent to the x-axis? Precalculus Geometry of an Ellipse Standard Form of the Equation 1 Answer A. S. Adikesavan May 11, 2016 (x −3)2 + (y −5)2 = 52. Expansion gives x2 +y3 − 6x −10y + 9 = 0 Explanation: x-axis touches the circle. So, the altitude from the center is the a imaxeon pty ltd abn